.541x^2+4.3738x+6.76=0

Solution for .541x^2+4.3738x+6.76=0 equation:

.541x^2+4.3738x+6.76=0

a = .541; b = 4.3738; c = +6.76;
Δ = b2-4ac
Δ = 4.37382-4·.541·6.76
Δ = 4.50148644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.3738)-\sqrt{4.50148644}}{2*.541}=\frac{-4.3738-\sqrt{4.50148644}}{1.082}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.3738)+\sqrt{4.50148644}}{2*.541}=\frac{-4.3738+\sqrt{4.50148644}}{1.082}
$